Answer:
x = 10
Step-by-step explanation:
Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.5
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Answer:
T = 3.50 + 1.50G
Step-by-step explanation:
G = number of games
T = total cost
total cost = cost of shoes + cost per game
T = 3.50 + 1.50G
I'm not 100% positive, but it's my best guess.
All you do is use the a+b=c formula lets plug it in
15+b=35
15+20=35
35=35
The answer is 20
Answer:
6.517%
Step-by-step explanation:
This is a multi-year investment and we are not working with a $1 initial investment. There is no mention of compounding so we will use formula A=P0⋅(1+r)N with A=$18,434 and P0=$14,320. We do not know the value of r. However, N=4 years. Substituting the values we have $18,434=$14,320⋅(1+r)4. Divide both sides of the equation by $14,320. Next, take the fourth root of both sides of the equation and subtract 1 to find the decimal form of r.
$18,4341.287291.065170.06517=$14,320⋅(1+r)4=(1+r)4=1+r=r
Finally, convert r to a percent.
r=0.06517×100%=6.517%