Ashley is riding her bicycle. She rides at a speed of

In the scale drawing, what will the length of the east, south, west, and north side of the backyard be?

Y_Kistochka [10]

Answer:

One cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Step-by-step explanation:

7 0

2 years ago

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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 0.499, \sigma = 0.002$

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.504 - 0.494}{0.002}$

$Z = 2.5$

$Z = 2.5$ has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.496 - 0.494}{0.002}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0

3 years ago

Mark the statements that are true.

lara [203]

Answer:

Correct answers:

A. An angle that measures $\frac{\pi}{6}$ radians also measures $30^o$

C. An angle that measures $180^o$ also measures $\pi$ radians

Step-by-step explanation:

Recall the formula to transform radians to degrees and vice-versa:

$\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\ \\\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians$

Therefore we can investigate each of the statements, and find that when we have a $\frac{\pi}{6}$ radians angle, then its degree formula becomes:

$\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians\\\angle\,degrees=\frac{180^o}{\pi} \,* \,\frac{\pi}{6} \\\angle\,degrees=\frac{180^o}{6} \\\angle\,degrees=30^o$