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Lina20 [59]
4 years ago
7

What does iron (iii) hydroxide decomposes into

Chemistry
1 answer:
abruzzese [7]4 years ago
8 0
Ferric hydroxide decomposes to ferric oxide (iron(iii) oxide or rust) and water.
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What is found only in an experimental investigation?
andreev551 [17]
 Experimental investigations<span> involve a process in which a "fair test" is designed and variables are actively manipulated, controlled, and measured in an effort to gather evidence to support or refute a </span>causal relationship<span>. Experimental investigations have a control group which does not receive any treatment. A classic example is "What is the effect of light color on plant growth?" In this experiment, the variable color of light is changed by the student. The student may compare red light to green light to natural light.


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In which biome do plants grow close to each other and close to the ground in order to resist the cold?
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Explanation:

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10. Which of the following mirror is used to form smaller image
vitfil [10]

Answer:

Correct answer is b) convex mirror

Explanation:

A convex mirror, which bulges outward, reflects at a wider angle near its edges than at its center, creating a slightly distorted image that's smaller than actual size. Convex mirrors have many uses. The smaller size of the images means that you can see more with these surfaces, hence their use in safety mirrors.

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4 years ago
What is the chemical compound for ammonia, nitrates, nitrous oxide, nitrogen gas, and nitrites?
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8 0
3 years ago
The rate constant of a reaction is 4.7×10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C?
vodomira [7]

Answer:

k is 3,18*10⁻² s⁻¹ at 75°C

Explanation:

following Arrhenius equation:

k= k₀*e^(-Ea/RT)

where k= rate constant , k₀= frequency factor , Ea= activation energy , R= universal gas constant T=absolute temperature

then for T₁=25°C =298 K

k₁= k₀*e^(-Ea/RT₁)

and for T₁=75°C = 348 K

k₂= k₀*e^(-Ea/RT₂)

dividing both equations

k₂/k₁= e^(-Ea/RT₂+Ea/RT₁ )

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )]

replacing values

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )] = 4,7*10⁻³ s⁻¹ *e^[-33.6*1000 J/mol /8.314 J/molK*(1/ 348 K -1/298 K )] = 3,18*10⁻² s⁻¹

thus k is 3,18*10⁻² s⁻¹ at 75°C

6 0
4 years ago
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