Because it requires more energy to create a neutron from a proton than it does to create a proton from a neutron, protons were formed more frequently than neutrons in the early universe. The correct answer is option b.
To find the answer, we need to know more about the early universe.
<h3>How the formation of proton over neutrons was favored in the early universe?</h3>
- A neutron is produced with greater energy than a proton.
- However, later on, some of the protons were changed into neutrons.
- Contrary to some claims, the proton is a stable particle that never decays, but the neutron is unstable outside of the nucleus and decays with a half life of around 10.5 minutes.
- However, very few would have had time to decay on the timeline you mention in your question.
- Every matter particle should have been accompanied by an antimatter particle, and every proton, neutron, and electron, by an anti-neutron and a positron, respectively.
- Where did all the antimatter go is the great mystery. There have been a few attempts to explain this, but they have failed.
Thus, we can conclude that, the correct answer is option b.
Learn more about the early universe here:
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The pressure of the carbon dioxide will be 0.09079 atm.
<h3>What is partial pressure?</h3>
The pressure exerted by the individual gas is known as partial pressure.
The partial pressure is given as

In a mixture of carbon dioxide and oxygen, 40.0% of the gas pressure is exerted by oxygen.
If the total pressure is 115 mmHg.
The total pressure in atm will be
P = 115 mmHg
P = 0.15132 atm
We have

Then the pressure of the carbon dioxide will be 0.09079 atm.
More about the partial pressure link is given below.
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Answer:
it's the regolith
hope this helps you
C Horizon - Also called regolith: the layer beneath the B Horizon and above the R Horizon. It consists of slightly broken-up bedrock. Plant roots do not penetrate into this layer; very little organic material is found in this layer. R Horizon - The unweathered rock (bedrock) layer that is beneath all the other layers.
Number of electron pairs = \frac{1}{2}[V+N-C+A]
2
1
[V+N−C+A]
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
SbCl_5SbCl
5
:
In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.
The number of electron pairs are 5 that means the hybridization will be sp^3dsp
3
B and geometry of the molecule will be trigonal bipyramidal.
Answer:
X= Be
Y= B
Z=O
Explanation:
From the description of the compound XCl2, among the options listed only beryllium can form such compound with three lone pairs in the two chlorine atoms and no lone pair on the central atom X.
From the description of YCl3, only Boron among the options listed can form such a compound with no lone pair on the central atom and three lone pairs on each of the chlorine atoms.
From the description of ZCl2, only oxygen forms the compound OCl2 among the elements listed where oxygen possesses two lone pairs and each chlorine atom possesses three lone pairs each.