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makvit [3.9K]
3 years ago
10

describe how a physical property, such as mass or texture, can change without causing a chance in the substance?

Chemistry
2 answers:
OLga [1]3 years ago
7 0
Mass can't be changed, It is not variable so it will stay the same in any condition. Texture on the other hand is variable it will change under the pressure or the atmosphere.
Verizon [17]3 years ago
5 0

mass cannot change as it is not a variable :)
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What is the type of mutation represented by the amino acid sequence below?
Ilia_Sergeevich [38]

Answer:

Substitution mutation

Explanation:

A substitution mutation is a type of mutation in which one or more nucleotide base is replaced by another in a sequence. This will result in the replacement of one or more amino acid in the amino acid sequence.

This is the case in this question where the original amino acid sequence was given as: Leucine – Alanine – Glycine – Leucine. After mutation, the following mutated sequence was produced: Leucine – Alanine – Valine – Leucine.

As illustrated above, one would notice that there is replacement of GLYCINE amino acid by VALINE in the mutated sequence, hence, it is an example of SUBSTITUTION MUTATION.

6 0
3 years ago
High temperature refrigeration is that produced by ____. A. heat from a furnace B. an air-conditioning system C. the vegetable c
seropon [69]

Answer:

B. an air-conditioning system.

Explanation:

Refrigeration is defined as a process of cooling a system to lower temperature below the surrounding temperature while the removed heat is rejected at higher temperatures.

Heat pumps use the heat output of the refrigeration process, which may also be designed to be reversible, but are otherwise similar to air conditioning units.

4 0
3 years ago
What is the hybridization and shape for an XeF6 2+ molecule?
Anna11 [10]

Answer:

Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²

Explanation:

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²

Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48

Ca. #Substrate e⁻ = 6F = 6(8) = 48

#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs

#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs

BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²    

XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)      

8 0
3 years ago
15. Which is not a zone in the three-layered structure of the ocean relating to density?
SSSSS [86.1K]
I believe the last one
4 0
3 years ago
Read 2 more answers
Give an example of an object that has potential energy
fredd [130]

Answer:

A book on a shelf

Explanation:

4 0
3 years ago
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