All categories

3 years ago

2x - y = 64x-y13anch

Mathematics

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

x=-7, y= -20

Step-by-step explanation:

2x - y =6

x - y = 13

when I subract (x-y =13 ) from (2x-y =6)

2x -y =6

-x +y=-13

______________

x = -7

substitute x=-7 in the second equation

-7 - y =13

-y = 13 +7

-Y = 20

Y=-20

x=-7, y= -20

jolli1 [7]3 years ago

5 0

Answer:

x= -7/6

y= -25/3

Step-by-step explanation:

2x-y =6

4 x-y =13

Firstly, 4x-y=13(-) =>> - 4x+y=-13

Then we make the sum and result 6x= -7. Result x= -7/6.

We need to find y. So:

-y= 6-2x =>> y= -6 +2x =>> y= -6 +2*(-7/6) =>> y= -6-7/3 =>> y=(-18-7)/3 =>>y= -25/3

You might be interested in

Create an equation that represents a parabola that opens upward

algol13

For a parabola that opens upward, it must be a quadratic equation whose coefficient of x2 is a positive number.

So, I'll say x2+5x+6.

8 0

3 years ago

2 easy questions, 6th grade

Gnoma [55]

Answer:

36 and 6. 2.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by: