A company policy requires that, for every 50 employees, there must be 3 supervisors. If there are 276 supervisors at the company
2 answers:
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The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.
The mass of the particles moving in river is proportional to the sixth power of 2, or
miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship 
, for some constant k.
For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.
So, the key here is proportional. We can set up two proportions and cross multiply.
Cancelling our x's (because we don't need to solve for them), we have
To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.
![\sqrt[6]{y^6} = \sqrt[6]{960}](https://tex.z-dn.net/?f=%20%5Csqrt%5B6%5D%7By%5E6%7D%20%3D%20%20%5Csqrt%5B6%5D%7B960%7D%20)
Using a calculator, we see that![\sqrt[6]{960} = 3.14 \ miles \ per \ hour](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B960%7D%20%3D%203.14%20%5C%20miles%20%5C%20per%20%5C%20hour)
.
The mass of the particles moving in river is proportional to the sixth power of 2, or
For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.
So, the key here is proportional. We can set up two proportions and cross multiply.
Cancelling our x's (because we don't need to solve for them), we have
To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.
Using a calculator, we see that
The equation to derive the distance d is . The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).
Consider the two points (x1, y1) and (x2, y2)
The formula used for calculating the distance between the two points is
distance =
Given that,
The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)
Since this triangle makes 90°, it is a right-angled triangle.
Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).
Consider the length of the hypotenuse = d
So, using the distance formula, the length of the hypotenuse(d) is,
And the lengths of the other two legs of the given triangle are,
Length of the adjacent side: (x1, y1) to (x2,y1)
=
=
=
Length of the opposite side: (x2, y1) to (x2, y2)
=
=
=
Therefore, the derived distances for the given triangle are:
, (x2 - x1), and (y2 - y1).
Learn more about the distance between two points here:
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Answer:
Last option: 4
Step-by-step explanation:
The quadratic equation simplified: has the form:
In this case, you can identify that "a", "b" and "c" are:
To solve this quadratic equation by completing the square, Carlos should add to both sides of the equation. This is:
Then:
Therefore you can observe that the number he should add to both sides of the equation is: 4