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sukhopar [10]
2 years ago
12

Write down a differential equation of the form dy/dt = ay + b whose solutions have the required behavior as t → ∞. all other sol

utions diverge from y = 2.

Mathematics
1 answer:
nordsb [41]2 years ago
6 0

The ODE has an equilibrium point at

\dfrac{\mathrm dy}{\mathrm dt}=ay+b=0\implies y=-\dfrac ba

We want y=2 to be an unstable equilibrium solution - in other words, we want all solutions with initial condition y(t_0)=c for c near 2 to diverge from y=2 - so -dfrac ba=2.

Divergence from y=2 would require that for y>2, any solution is increasing, and for y, and solution is decreasing. In order for that to happen, we need

\dfrac{\mathrm dy}{\mathrm dt}=ay+b>0\implies y>-\dfrac ba

if y>2, and

\dfrac{\mathrm dy}{\mathrm dt}=ay+b

if y.

Now we just pick a,b to satisfy these conditions. An easy choice is a=1, which forces b=-2, so that one possible ODE would be

\dfrac{\mathrm dy}{\mathrm dt}=y-2

I've attached a plot of the slope field to demonstrate the behavior of the solutions.

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Answer:

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Since sin(x) is and odd function (a function where f(-a) = f(a) ).

-sin( ∅ ) = sin( -∅ )

On the other hand, we know that sin( ∅ ) = 1 / csc ( ∅ )

Another odd function, so the same as before applies.

-sin( ∅ ) = -1 / csc ( ∅ )

-sin( ∅ ) = 1 / csc ( -∅ )

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Answer:

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Jovani wanted to switch gyms. Fitness 19 charges a one time $39 cleaning fee and $17 per
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Answer:

Hi there!

Your answer is:

It will take 2.2 months for both gyms to be the same amount of money!

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Put them equal to each other:

39+17x = 50+12x

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2 years ago
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Given :-

  • a² - 2a - b² = 0
  • 2b + 2ab = 0

To find :-

  • Value of a and b .

Solution :-

<u>Taking</u><u> </u><u>second</u><u> </u><u>equation</u><u>:</u><u>-</u>

  • 2b + 2ab = 0
  • 2b ( 1 + a ) = 0
  • 2b = 0 or (1+a) = 0
  • b = 0 , a = -1

<u>Substitute</u><u> </u><u>in </u><u>first </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>

  • a² - 2a - b² = 0

<u>When </u><u>b </u><u>=</u><u> </u><u>0</u><u> </u><u>,</u>

  • a² - 2a - 0² = 0
  • a² - a = 0
  • a( a -1) =0
  • a = 0 , 1

<u>When </u><u>a </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>,</u>

  • (-1)² - 2*(-1) - b² = 0
  • 1 + 2 - b² = 0
  • b² = 3
  • b = ±√3

<u>Answer </u><u>:</u><u>-</u><u> </u>

  • a = 0,1 ; b = 0
  • a = -1 , b = ±√3
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