Question

Please help me with pythagoras.

Answer 1

Answer:

(q)

$cb \: = \sqrt{4 {}^{2} + {3}^{2} }$

$cb = 5$

$q = \sqrt{ {13}^{2} - {5}^{2} }$

$q = 12$

(r)

$cb = \sqrt{ {13}^{2} - {5}^{2} }$

$cb = 12$

$r = \sqrt{12 {}^{2} - 5 {}^{2} }$

$r = \sqrt{119}$

$r = 10.91$

(s)

$ab = \sqrt{20 {}^{2} - 16 {}^{2} }$

$ab = 12$

$s = \sqrt{12 {}^{2} + 8 {}^{2} }$

$s = 4 \sqrt{13}$

$s = 14.42$

Step-by-step explanation: