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2 years ago

What is 3 to the 4th power in standard form

Mathematics

2 answers:

nika2105 [10]2 years ago

6 0

Answer:

81, i think.

Step-by-step explanation:

sashaice [31]2 years ago

5 0

Answer:

Step-by-step explanation:

3 times 3 = 9

9 times 3 = 27

27 times 3 = 81

Can i have brainieslt please

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Samantha sends her son, Barry, to a preschool center on certain days. The cost of preschool is $45 per day along with a fixed mo

MAXImum [283]

Answer:

Step-by-step explanation:

We are given fixed monthly charge = $70.

The cost of preschool per day = $45.

Number of days = d.

Total cost of d days = cost per day × number of days + fixed monthly charge.

Therefore, we get equation

880 = 45×d+70

Now, we need to solve the equation for d.

Subtracting 70 from both sides, we get

880-70 = 45d +70-70

810=45d

Dividing both sides by 45, we get

$\frac{810}{45} =\frac{45d}{45}$

18=d.

Therefore,<em> 18 days Barry attended preschool last month.</em>

<em>Therefore, correct option is D option.</em>

4 0

2 years ago

X=-2y+16<br> 4x+8y=32<br> substitutional equation

Dahasolnce [82]

4(-2y + 16) + 8y = 32
-8y + 64 + 8y = 32
64 = 32
Answer: no solution

5 0

2 years ago

The graph of y=f(x) is shown below. Draw the graph of y=-f(x)

valkas [14]

Answer:

y = -f(x): reflection over x axis

Step-by-step explanation:

y = -f(x): reflection over x axis

8 0

2 years ago

Identify the equation of a line in point-slope form that passes through the point (-3,4) with a slope of -2

vova2212 [387]

Answer:

y = -2x - 2

Step-by-step explanation:

y = Mx + c

4 = -2(-3)+ c

4 =6+ c

c = -2

6 0

1 year ago

Let n be a natural number. Show that 3 | n3 −n

Vladimir [108]

Let $n=1$ . Then $n^3-n=1^3-1=0$ . By convention, every non-zero integer $n$ divides 0, so $3\vert n^3-n$ .

Suppose this relation holds for $n=k$ , i.e. $3\vert k^3-k$ . We then hope to show it must also hold for $n=k+1$ .

You have

$(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)$

We assumed that $3\vert k^3-k$ , and it's clear that $3\vert 3(k^2+k)$ because $3(k^2+k)$ is a multiple of 3. This means the remainder upon divides $(k+1)^3-(k+1)$ must be 0, and therefore the relation holds for $n=k+1$ . This proves the statement.

4 0

2 years ago