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Dmitriy789 [7]
3 years ago
11

How many solutions does a system of equations have that are lines that are parallel?

Mathematics
1 answer:
madam [21]3 years ago
5 0

To answer this question, you have to ask yourself, "What specifically is a solution to a system of equations?"

The answer to this question is: A solution is where the two lines intersect each other.

Now, you have to think, "Where do these two lines intersect each other?"

Well, one big factor is knowing that both of these lines are parallel to each other. That means they run alongside each other and never cross over.

If you put piece by piece together with this information, you can deduce that two parallel linear lines will never cross over each other and thus, have no solutions to them.

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4vir4ik [10]
Let's call the number of rows 'R' . (Clever ?)

There are (3x -2) trees in each row, and there are 'R' rows,
so the total number of trees is [ R times (3x-2) ].

But the problem told you that the total number of trees is (24x-16).
So
       R(3x - 2) = (24x - 16)

For a quick, happy ending, how about factoring '8' out of the right side:

       R(3x - 2) = 8(3x - 2)

Is it jumping out at you yet ?
If not, then divide each side by (3x - 2) :

     <em>  <u> R      =      8</u></em>

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5 0
3 years ago
Mr. Fernández packed 31 red apples and 41 green apples into a box for a customer. He packed 8 boxes like this. Mr. Fernández use
ratelena [41]
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3 years ago
The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of
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The length of longer base is 41 feet

<em><u>Solution:</u></em>

<em><u>The area of trapezoid is given as:</u></em>

A = \frac{a+b}{2} \times h

Where , "a" and "b" is the length of base and "h" is the height

The length of one base of a trapezoid is 19 less than five times the length of the other base

a = 19 less than fives times b

a = 5b - 19

Height of 18 feet and an area of 477 ft squared

h = 18 feet

area = 477 square feet

<em><u>Substitute the values in above formula</u></em>

477=\frac{5 b-19+b}{2} \times 18\\\\477=(6b-19) \times 9\\\\477 = 54b-171\\\\54b = 648\\\\b=12

Therefore,

a = 5b - 19 = 5(12) - 19 = 41

Thus length of longer base is 41 feet

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Step-by-step explanation:

this is the answer

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Dan says he ran twice as far as Karim. Give three possibilities for the distances each could have run.
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