Question:
Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.
Answer:
1. the longer frame (B) has the shorter width
2. the shorter width is 6 3/7 inches, area divided by length
Step-by-step explanation:
The relation between area, length, and width is ...
A = LW
Then the width is ...
W = A/L . . . . . inversely proportional to length
1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.__
2. The width of frame B is ...
W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in
-Alan Becker
The area of the small poster is 160 inches square
<h3>How to determine the area</h3>
From the information given, we have the poster to take the form of a rectangle
The formula for area of a rectangle is;
Area = length × width
For the smaller poster created using a scale of factor 2/3
Length = 2/ 3 × 24
Length = 16 inches
Width = 2/ 3 × 15
Width = 10 inches
Substitute into the formula
Area = 16 × 10
Area = 160 inches square
Thus, the area of the small poster is 160 inches square
Learn more about area here:
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Answer:
± 
Step-by-step explanation:
Given
x² = 20 ( take the square root of both sides )
x = ±
Answer:
The expression to the statement in roaster form is:
{1,2,3,4,5,6}
Step-by-step explanation:
<em>" To express the set in roster form the elements of a set are listed within the curly brackets and are separated by commas " .</em>
We are given a statement as:
" The set of natural numbers less than 7" is represented in roaster form as:
{1,2,3,4,5,6}
( since, the natural numbers are the positive integers (whole numbers) 1, 2, 3, etc. and we asked to find the numbers less than 7).
Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:
Part (a):
In how many ways can one component of each type be selected?
The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4
Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways
Part (b):
In how many ways can components be selected if both the
receiver and the compact disc player are to be Sony?
The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4
Therefore, the number of ways components can be selected if both the
receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12
Part (c)
In how many ways can components be selected if none of them are Sony?
The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3
Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108
Part (d):
In how
many ways can a selection be made if at least one Sony component is
to be included?
The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108
Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132
Part (e):
If someone flips switches on the selection in a
completely random fashion, what is the probability that the system
selected contains at least one Sony component?
The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132
Therefore, the probability that a system
selected at random contains at least one Sony component is given by 132 / 240 = 0.55
Part (f):
If someone flips switches on the selection in a
completely random fashion, what is the probability that the system
selected contains exactly one Sony
component? (Round your answer to three decimal places.)
The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36
Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99
Therefore, the probability that a system
selected at random contains exactly one Sony
component is given by 99 / 240 = 0.413
