Question

Given that ƒ(x) = x² + 4x, evaluate ƒ(-2)

Answer 1

$f(x)= x^{2} +4x \\ f(-2)= (-2)^{2} +4(-2) \\ =4-8 \\ =-4$

Answer 2

F(-2)=(-2)2+4(-2)
4-8
-4