Answer:
A, C, D, F
Step-by-step explanation:
Given the expression : (3/5)³
Recall :
a^b where, a = base ; b = exponent
In ; (3/5)^3
Base = 3/5 ; exponent = 3
Similarly ;
a^b = a in b places
(3/5)^3 = (3/5) * (3/5) * (3/5)
(3/5) * (3/5) * (3/5) = (3*3*3) / (5*5*5) = 27/125
Hence, A, C, D and F are all correct
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
Step-by-step explanation:
We will use the distance formula to solve.
<em>Read more about using the </em><em>distance formula</em><em> here: brainly.com/question/15691280</em>
2, No solution
3, Infinite many solutions
4, (0,-3)
i hope i was able to help!! so sorry if i made a mistake
I'm assuming you mean 2^(5)(4/3)(2).
So multiplying all of the powers together yields 2^(40/3)
