Answer:
(b) 
Step-by-step explanation:
Let E: Event of getting a 3 in the spinner.
So, the number of favorable outcomes = 11
Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}
= {13 +10 +11+16+11} = { 61}
So, the total number of outcomes = 61

So, here 
Answer:
a. 
b. 
Step-by-step explanation:
First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

The rate is negative as it represents the amount of caffeine leaving the body at certain time.
try and see if it =0
Step-by-step explanation:
This deals with factoring multi-variable polynomials.