Hello there!
<span>Find the volume of the cone. Use 3.14 as an approximation for pi. Round the answer to two decimal places.
A cone with radius of circular base of 6 centimeters and a height of 7 centimeters.
</span><span>C. 263.76cm3
</span>
Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer: 7: 17
Step-by-step explanation:
This doesn't really make sense but it's how I do it
8:02 = 7:62
7:62
<u> - 45</u>
7: 17
length (l) =54
breath (b) =72
l²+b²= diagonal²..........(Pythagoras theorem) and (all sides of rectangle are 90degree)
(54)²+(72)²=diagonal²
2916+5184=diagonal²
8100=diagonal²
90= diagonal.............(taking square root)
length of diagonal is 90ft
i hope it helps
have a nice day and thanks for asking this question