1) slope = (y₂-y₁)/(x₂-x₁)
Let A and B be A(4,-6) and B(0,2) ;
m = [2-(-6)]/[0-4) = (2+6)/(-4) → m = -2
2) Midpoint = value of x of the midpoint = (x₁+x₂)/2
value of y of the midpoint = (y₁+y₂)/2
x(midpoint) = (4+0)/2 → x= 2
y(midpoint) = (-6+2)/2 → y= - 2, so Midpoint M(2,-2)
3) Slope of the perpendicular bisector to AB:
The slope of AB = m = -2
Any perpendicular to AB will have a slope m' so that m*m' = -1 (or in other term, the slope of one is inverse reciprocal of the second, then if m =-2, then m' = +1/2 ; Proof [ (-2)(1/2) = -1]
4) Note that the perpendicular bisector of AB passes through the midpoint of AB or M(2,-2). Moreover we know that the slope of the bisector is m'= 1/2
The equation of the linear function is :
y = m'x + b or y = (1/2)x + b. To calculate b, replace x and y by their respective values [in M(-2,2)]
2= (1/2).(-2) + b → 2 = -1 + b → and b= 3, hence the equation is:
y = (1/2)x + 3
What's your question so I could help?
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For palarell lines, slope are equal.
slope of first line = (y2 - y1)/(x2 - x1) = (-7 - 9)/(-12 - 8) = -16/-20 = 4/5
equation of a line passing through a point is given by: y - y1 = m(x - x1); where (x1, y1) = (-5, -15) and m = 4/5.
Therefore equation of the line is y - (-15) = 4/5(x - (-5))
y + 15 = 4/5(x + 5)
