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insens350 [35]
3 years ago
15

What is the slope of the line through (2,-1) and (-2,-3)

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Answer:

y=1/2x-2

Step-by-step explanation:

1. Find slop by subtracting y values over subtracting x values, which will get you the m value

-1+3 / 2+2 = 1/2

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Answer:

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Step-by-step explanation:

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A population of 800 spiders is decreasing at a rate of 14% each week. How many weeks will it take for the population to be half
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5 0
3 years ago
if the vertex of a parabola is (-4,6) and another point on the curve is (-3,14), what is the coefficient of the squared expressi
Softa [21]

Answer:

8

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, 6 ), thus

y = a(x + 4)² + 6

To find a substitute (- 3, 14) into the equation

14 = a(- 3 + 4)² + 6 ( subtract 6 from both sides )

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3 0
3 years ago
What is the slope of a line that contains the points (2,-7) and (-1, -6)
Bogdan [553]

Answer:

Slope = - 1/3

Step-by-step explanation:

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8 0
2 years ago
Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

4 0
3 years ago
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