Question

The function g(x) = x2 – 10x + 24 is graphed on a coordinate plane. Where will the function cross the x-axis?

Answer 1

Let g(x) = 0

(x-4)(x-6) = 0

x = 4 or 6

So the x-intercepts are (4,0), (6,0)

Answer 2

Answer:

function crosses the x axis at the points (4,0) and (6,0)

Step-by-step explanation:

The given function is $g(x)=x^2-10x+24$

When the graph crosses the x-axis then g(x)=0

Thus, we have

$x^2-10x+24=0$

Write the middle term as : -10x = -6x-4x

$x^2-6x-4x+24=0$

Factored out GCF

$x(x-6)-4(x-6)=0$

Now, factored out the common term (x-6)

$(x-6)(x-4)=0$

Apply the zero product property

$(x-6)=0,(x-4)=0$

Solve for x

$x=6,x=4$

Therefore, the function crosses the x axis at the points (4,0) and (6,0)