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Art [367]
3 years ago
11

Cathy attended a birthday party where the guests took their shoes off to jump in a bouncy castle. She made this graph to compare

the number of people at the party to the shoes on the rack.
What statement best describes the relationship?
A. The relationship is not proportional because the graph does not continue forever.
B. The relationship is not proportional because it does not include negative values.
C. The relationship is proportional because its graph is a straight line through the origin.
D. The relationship is proportional because the number of shoes is always greater than the number of people.
Mathematics
2 answers:
Alexeev081 [22]3 years ago
4 0

Answer:

Its C.

Step-by-step explanation:

irakobra [83]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Pizza

\\ x^{2} \neq  \lim_{n \to \infty} a_n

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7 0
3 years ago
PLEASE NEED HELP
expeople1 [14]

Answer:

D) 96%

Step-by-step explanation:

If you take 96% of 28.6 you get 27.6 so it fits

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2 years ago
Membership in Mensa requires an IQ score above 131.5. Nine candidates take an IQ test, and they have a mean IQ score of 133. IQ
rodikova [14]

Answer:

a) P(X\geq 133)=P(\frac{X-\mu}{\sigma}\geq \frac{133-\mu}{\sigma})=P(Z\geq \frac{133-100}{15})=P(Z\geq 2.2)

And we can find this probability using the complement rule:

P(Z\geq 2.2)=1- P(z

b) P(\bar X\geq 133)=P(\frac{\bar X-\mu}{\sigma_{\bar x}}\geq \frac{133-\mu}{\sigma_{\bar x}})=P(Z\geq \frac{133-100}{5})=P(Z\geq 6.6)

And we can find this probability using the complement rule:

P(Z\geq 6.6)=1- P(z

c) No. The mean can be lower than 131.5 if we find the probability:

P(\bar X\leq 133)=P(\frac{\bar X-\mu}{\sigma_{\bar x}}\leq \frac{131.5-\mu}{\sigma_{\bar x}})=P(Z\leq \frac{131.5-100}{5})=P(Z\leq 6.3)

P(Z\leq 6.3) \approx 1

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

A.    If 1 person is randomly selected from thegeneral population, find the probability of getting someone with anIQ score of at least 133.

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We are interested on this probability

P(X\geq 133)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X\geq 133)=P(\frac{X-\mu}{\sigma}\geq \frac{133-\mu}{\sigma})=P(Z\geq \frac{133-100}{15})=P(Z\geq 2.2)

And we can find this probability using the complement rule:

P(Z\geq 2.2)=1- P(z

And the probability is calculated from the normal standard table or with excel.

B.     If 9 people are randomly selected,find the probability that their mean IQ score is at least 133.

For this case since the distribution for the random variable X is normal then the distribution for the sample mean is also normal and given by:

\bar X = \sim N(\mu= 100 ,\sigma_{\bar x}= \frac{15}{\sqrt{9}}=5)

The new z score is defined as

z=\frac{x-\mu}{\sigma_{\bar x}}

If we apply this formula to our probability we got this:

P(\bar X\geq 133)=P(\frac{\bar X-\mu}{\sigma_{\bar x}}\geq \frac{133-\mu}{\sigma_{\bar x}})=P(Z\geq \frac{133-100}{5})=P(Z\geq 6.6)

And we can find this probability using the complement rule:

P(Z\geq 6.6)=1- P(z

And the probability is calculated from the normal standard table or with excel.

C.     Although the results are available,the individual IQ test scores have been lost. Can it be concluded that all 9 candidates have IQ scores above 131.5 so that they allare eligible for Mensa membership?

No. The mean can be lower than 131.5 if we find the probability:

P(\bar X\leq 133)=P(\frac{\bar X-\mu}{\sigma_{\bar x}}\leq \frac{131.5-\mu}{\sigma_{\bar x}})=P(Z\leq \frac{131.5-100}{5})=P(Z\leq 6.3)

P(Z\leq 6.3) \approx 1

6 0
3 years ago
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What is the answer to this math problem -4(17)
saveliy_v [14]

Answer:

-4(17)=-68     hope this helps :)

Step-by-step explanation:

Another way of saying -4(17)   is  -4x17=-68

3 0
4 years ago
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Scientists researching the effect of dietary supplements such as multivitamins and supplements of folic acid, magnesium or zinc
yarga [219]

Answer: Null hypothesis : H_0: p_1=p_2

Alternative hypothesis : H_a: p_1\neq p_2

Step-by-step explanation:

Let p_1 be the proportion of women using supplements and p_2 be the proportion of women who did not to have died during that period .

Then the set of hypothesis for testing if the proportion of women elderly women who use dietary supplements is different than those who do not will be :-

Null hypothesis : H_0: p_1=p_2     [∵ it takes equality sign]

Alternative hypothesis : H_a: p_1\neq p_2    [∵ it takes ≠ sign to show difference]

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