Answer: The length of segments between this point and the vertices of greater base are
and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,

Let, DP =x
⇒ 
⇒ 33 +11x = 18x
⇒ x = 33/7= 
Thus, PD= 
But, AP= PD + DA
AP= 
Now, let PC =y,
⇒ 
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18
To solve this, take the total distance (5,280) divide by the average step (42).
5,280/42 = 125.714
<span>A) 2x - 4y = 10
B) 7x - 9y = 12
Multiplying equation A by -3.5
A) -7x +14y = -35 then adding B
B) </span><span><span>7x - 9y = 12</span>
5y = -23
y = -4.6
</span>
2x -4*-4.6 = 10
2x + 18.4 = 10
2x = -8.4
x = -4.2
It has one solution (-4.2, -4.6)
Answer: y+9=-2(x-9)
Step-by-step explanation:
The point-slope equation is
. All we have to do is fill in all the values except for y and x.
To find m, you use
. Since we are given 2 points, we cna plug them in.
. Now that we have our slope m, we can fill in the point slope equation.

