Recall that
d/dx sech(x) = - sech(x) tanh(x)
d/dx tan⁻¹(x) = 1/(1 + x²)
Then by the chain rule,
dy/dx = - sech(x) tanh(x) / (1 + x²)
Answer:
The slope of the a straight line is given by the ratio of the Rise to the Run
of the line. The rise between the given points is zero.
The slope of the line that passes through the points (4, 10) and (1, 10) is zero.
Step-by-step explanation:
The given points are; (4, 10) and (1, 10)
The slope of a line, m, is given by the following formula;
Where;
(x₁, y₁) = (4, 10) and (x₂. y₂) = (1, 10), we get;
The slope of the line that passes through the points (4, 10) and (1, 10) is 0.
Y=2x+2
(y=mx+c
m-slope/gradient
c-y intercept)
What are the answer choices?
