v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.
Let the weight of each checking bag is w kg. So we can write:
2 x (Weight of a checking bag) + Weight of Backpack = 35
Using the values, we get:
2w+ 4 = 35
Using this equation we can find the weight of each checking bag, as shown below.
2w = 31
w = 31/2
w = 15.5
Thus, the weight of each checking bag is 15.5 kg
</span>
Answer:
2.88
Explanation:
If you break down the equation we see that 8 is the number of boxes and 1.44 is the price of each box. So if you wanted to change the equation the formula would be: (1.44)x = cost so if you wanted to figure out how much 2 boxes would be, you just plug in 2 for x and you get (1.44)2 = 2.88
Answer:
Triangle Sum Theory
Step-by-step explanation:
You add all the angles to get 180
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
