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Nimfa-mama [501]
3 years ago
6

What is the approximate side length of the square

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

Option C. 4.2 units

Step-by-step explanation:

Diagonals of a square intersect each other at 90°.

Therefore, From the right angle triangle formed at the center will be,

(Length of square)² = 3² + 3² [By Pythagoras theorem}

Length of the square = \sqrt{9+9}=\sqrt{18}

                                   = 4.24 units

                                   ≈ 4.2 units

Option C is the answer.

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Read the following poem:
pentagon [3]

Answer:

7, I believe. I have to fill in the extra character space, so I hope you have a nice day :)

6 0
2 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
allochka39001 [22]

Answer:

I think b) is the answer I solve it but

8 0
2 years ago
The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?
Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

<u><em>Step 1: You need to create a equation first:</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

<u><em>How did I make the equation?</em></u>

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13  ALL CONSECUTIVE ODD NUMBERS

<u><em>Step 2: Simplifying the equation</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

<u><em>Step 3: Solving the equation, with explanation</em></u>

5n + 20 = 2555       Subtract 20 on both sides

        5n = 2535        Isolate the variable by dividing 5 on both sides

          n = 507

<u><em></em></u>

<u><em>Step 4: Plug in the value</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8

507,  507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

<u><em>Step 5:  Solve the sum of the first, third, and last integer</em></u>

507 + 511 + 515 = 1533

<u><em>Step 6: THE ANSWER</em></u>

1533

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>
8 0
3 years ago
If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor
choli [55]
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
5 0
2 years ago
8/9 with a exponet of 0
svetoff [14.1K]

Answer:

1

Step-by-step explanation:

this is because the number is not getting multiplied by anything.

3 0
3 years ago
Read 2 more answers
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