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Nimfa-mama [501]
3 years ago
6

What is the approximate side length of the square

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

Option C. 4.2 units

Step-by-step explanation:

Diagonals of a square intersect each other at 90°.

Therefore, From the right angle triangle formed at the center will be,

(Length of square)² = 3² + 3² [By Pythagoras theorem}

Length of the square = \sqrt{9+9}=\sqrt{18}

                                   = 4.24 units

                                   ≈ 4.2 units

Option C is the answer.

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vampirchik [111]

Answer:

1000

Step-by-step explanation:

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3 years ago
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Which inequality is true? A. |-15| > |-19| B. |-16| < |13| C. |-15| > |12| D. |12| < |-8| E. |-19| > |-20|
Olin [163]
C. is the answer.
The modulus or absolute value function of a real number x is the non-negative value of x without regard to its sign.
The only correct option is C. because 15 is indeed greater than 12.
Options A., B., D. and E. are wrong.
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3 years ago
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Differentiate with respect to x (6-2x)^3​
olga55 [171]
-6(6-2x)^2 by chain rule
6 0
2 years ago
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A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
How do you add 1/3 and 1/6 together?
Leya [2.2K]
Multiply the numerator and denominator of the first question by 2 in order for both of the denominators to be the same.

1*2=2
3*2=6

Now that the denominators are the same, we can simply add the numerators and simplify if possible.

(2/6)+(1/6)= (3/6)

(3/6)= (1/2)

Final answer: 1/2
8 0
3 years ago
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