Let x be the yard length, then if <span>the length of the yard is 10 feet more than 2 times the width, the length of the yard is 2x+10. The perimeter is 2 lengths + 2 widths, so P=2x+2(2x+10) .
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Since Sally <span>needs 56 feet of fencing to do the job, P=56 ft. and
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<span>2x+2(2x+10)=56,
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</span><span>2x+4x+20=56,
</span><span>
</span><span>6x=56-20,
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</span><span>6x=36,
</span><span>
</span><span>x=6 ft. and 2x+10=12+10=22 ft.
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</span><span>Answer: The length of the yard is 22 feet</span>
C. y - 3 = 2/3(x-3)
Nothing much to do here except examine each equation and plug in the numbers to see if it's true.
a. y + 3 = 3/2(x+3)
Try 3,3
3 + 3 = 3/2(3+3)
6 = 3/2(6). And no need to go further, it's obviously not equal.
b. y - 3 = 3/2(x-3)
Try 3,3
3 - 3 = 3/2(3-3)
0 = 3/2(0). OK. Let's try 6,5
5 - 3 = 3/2(6-3)
2 = 3/2(3)
2 = 9/2 And it's not true, so check the next one.
c. y - 3 = 2/3(x-3)
Try 3,3
3 - 3 = 2/3(3-3)
0 = 0. Check 6,5
5 - 3 = 2/3(6-3)
2 = 2/3(3)
2 = 2. Good. Both sample points work. This is the correct answer.
Just to be sure, let's check the next option
d. y + 3 = 2/3(x+3)
Try 3,3
3 + 3 = 2/3(3+3)
6 = 2/3(6). And doesn't match.
Answer:
-4 equals p=2 and a and R are at point Y downwards.
Answer:
12566.4 mm²
Step-by-step explanation:
The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.
TSA = Total Surface Area
CSA = Curved Surface Area
TSA of open cylinder = CSA of cylinder + area of base or top
= 2πrh + πr²
= πr(2h + r)
From the above question:
r = 50mm
h = 15mm
Hence,
= π × 50 (2 × 15 + 50)
= π × 50 (30 + 50)
= π × 50(80)
= π × 4000
= 12566.370614mm²
Approximately = 12566.4 mm²
The Surface Area of the petri dish with no lid = 12566.4 mm²
Answer:
Kiwis because there are 12 and cost less then nectarienes
Step-by-step explanation:
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