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Slav-nsk [51]
3 years ago
15

Which of the following situations might convince an employer to choose a nonqualified retirement plan over a qualified profit-sh

aring plan?
A) The employer, a closely held C Corporation, is in the 15% income tax bracket and the sole owner of the employer is in the 35% income tax bracket.
B) The employer only wants to meet the organization's objectives of attracting executives, retaining executives, and providing for a graceful transition in company leadership.
C) The employer is not concerned with providing retirement benefits to the rank and file employees.
D) The employer is not willing to pay high administrative costs.
E) All of the above.
Business
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

All the options might convince to an employer to choose a nonqualified retirement plan over a quialified plan.

en A). the owner of the corporation would use a nonqualified plan because the income tax rate of the business is lower than the owner´s tax rate.  

B) Is a true statement.  as nonqualified plans are typycally only stablised to benefit the executive and there are no requirements to benefit thr rank and file

C)

would cause an employer to choose a nonqualified plan because a nonqualified plan requires less administrative costs than a profit sharing plan

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Distinguish between planned economy and mixed economy?​
Anettt [7]

Answer:

CHECK THE EXPLANATION.

Explanation:

A planned economy is a type of economic system where investment, production and the allocation of capital goods takes place according to economy-wide economic plans and production plans. A planned economy may use centralized, decentralized, participatory or Soviet-type forms of economic planning whereas a mixed economy is an economy organized with some free market elements and some socialistic elements, which lies on a continuum somewhere between pure capitalism and pure socialism. ... Mixed economies socialize select industries that are deemed essential or that produce public goods.

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2 years ago
Who is responsible for the financial consequences of a minor's driving?
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Answer: b. the minor's parents or guardians are responsible

The minor's parents or guardians are responsible for the financial consequences of a minor's driving, whether the minor has a license or not. It is a law under a legal concept called "vicarious liability" imposed in most states in the U.S


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3 years ago
Clauses in labor agreements that provide for quarterly cost-of-living adjustments in wages based on changes in the consumer pric
IrinaVladis [17]

Answer:

c. escalator clauses

Explanation:

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8 0
3 years ago
Raul, the CEO of Color Paints Inc. noticed that their plant loses considerable time daily because the assembly line has to be cl
ValentinkaMS [17]

Answer:

cross-functional team

Explanation:

According to my research on different team organizational structures, I can say that based on the information provided within the question this team exemplifies a cross-functional team. This type of team is defined as a team of various people all of which are experts in different areas but yet are all working together towards the same goal. Which is what the employees of Color Paints Inc. are exhibiting.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

7 0
4 years ago
The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

3 0
3 years ago
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