Answer:
u = -5/9
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-3(u + 2) = 5u - 1 + 5(2u + 1)
<u>Step 2: Solve for </u><em><u>u</u></em>
- Distribute: -3u - 6 = 5u - 1 + 10u + 5
- Combine like terms: -3u - 6 = 15u + 4
- Add 3u to both sides: -6 = 18u + 4
- Subtract 4 on both sides: -10 = 18u
- Divide 18 on both sides: -10/18 = u
- Simplify: -5/9 = u
- Rewrite: u = -5/9
<u>Step 3: Check</u>
<em>Plug in u into the original equation to verify it's a solution.</em>
- Substitute in <em>u</em>: -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
- Multiply: -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
- Add: -3(13/9) = -25/9 - 1 + 5(-1/9)
- Multiply: -13/3 = -25/9 - 1 - 5/9
- Subtract: -13/3 = -34/9 - 5/9
- Subtract: -13/3 = -13/3
Here we see that -13/3 does indeed equal -13/3.
∴ u = -5/9 is a solution of the equation.
Answer:multiply by three
Step-by-step explanation:
Think the 4 less than but not equal to as a equal sign
step 1. isolate the variable ( variable must stand alone)
step 2. subtract 12n -12n=0
step 3. since you subtract 12n from the left you must do the same to the right.
step 4. 13n - 12n =1n
step 5. the equation should look like this -4 less than but not equal to 1n
step 6. isolate the variable n
step 6. divide 1n/1 on the right and on the left -4/1 it equals -4
so, n is -4
Answer:
m<RPQ = 22°
Step-by-step explanation:
Given:
m<SRQ = 90°
PS = PQ
m<SQR = 46°
Required:
m<RPQ
Solution:
m<SQR + m<SRQ + m<RSQ = 180°
Substitute
46° + 90° + m<RSQ = 180°
m<RSQ = 180° - 136°
m<RSQ = 44°
Find m<PSQ:
m<PSQ = 180° - m<RSQ (Angles on a straight line
m<PSQ = 180° - 44° (Substitution)
m<PSQ = 136°
Find m<RPQ:
∆QSP is an isosceles triangle with two equal base angles. Therefore:
m<RPQ = ½(180° - 136°)
m<RPQ = 22°
Answer:
The American bison is 10 miles per hour faster. It can run at 40 miles per hour.
Step-by-step explanation:
See the picture for the conversion. I used unit multiplies to change feet to miles and seconds to minutes.
