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saul85 [17]
3 years ago
11

The following table shows the number of hours some high school students in two towns spend riding the bus each week:

Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

Part A:

The five number summary is consisting of : Median or 2nd quartile(Q2), 1st quartile(Q1), 3rd quartile(Q3), Lowest and Highest values.

For creating the five number summary for each set, first we need to rearrange the data set in ascending order:

Town A : 3 4 5 5 6 7 9 9 20

Median is the middle value in the set. Here, the middle value is 6. So the median or second quartile(Q2) = 6. The lowest value is 3 and highest value is 20.

The median splits the remaining data into two sets. The first set is 3, 4, 5, 5. The median of this set is \frac{4+5}{2}= \frac{9}{2}  =4.5

So, first quartile (Q1) = 4.5

The other set is 7, 9, 9, 20. The median of this set is: \frac{9+9}{2}=\frac{18}{2}=9

So, third quartile (Q3) = 9

The interquartile range(IQR)= Q3 - Q1 = 9 - 4.5 = 4.5

Town B : 3 3 5 5 6 8 8 9 9

The middle value in the set is 6. So, the median or second quartile(Q2) =6. The lowest value is 3 and the highest value is 9.

The first set in the left of median is: 3 3 5 5 and median of this set= \frac{3+5}{2}=\frac{8}{2}=4

So, first quartile (Q1) = 4

The second set in the right of median is : 8 8 9 9 and the median of this set = \frac{8+9}{2}=\frac{17}{2}=8.5

So, third quartile (Q3) = 8.5

The interquartile range(IQR)= Q3 - Q1 =8.5 - 4 = 4.5

Part B:

A box plot is called symmetric when the median is in the middle of the box, that means Q2 should be equally distanced from Q1 and Q3.

For town A, distance between Q1 and Q2 = 6 - 4.5 = 1.5 and distance between Q2 and Q3 = 9 - 6 = 3. As the distances are different, so the box plot is not symmetric.

For town B, distance between Q1 and Q2 = 6 - 4 = 2 and distance between Q2 and Q3 = 8.5 - 6 = 2.5. As the distances are different, so this box plot is also not symmetric.

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solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
2 years ago
5 Michiko has a metal container in the shape of a cuboid. The container is 2.4 m long, 1.2 m wide and 0.6 m high. Michiko plans
konstantin123 [22]

Answer:

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

Step-by-step explanation:

Surface area of cuboid = 2lw + 2lh + 2hw

Length (l) = 2.4 m

Width (w) = 1.2 m

Height (h) = 0.6 m

SF = 2(2.4 × 1.2) + 2(2.4 × 0.6) + 2(0.6 × 1.2)

   = 5.76 + 2.88 + 1.44

   = 10.08 meter²

Paint coverage is 4.5 meter² per liter.

Total paint used in one coat =

                                              = 2.24 liters

Paint used in double coats = 2.24 × 2 = 4.48 liters

a) Size of one tin paint = 250 ml

1 liters = 1000 ml

4.48 liters = 4.48 × 1000 = 4480 ml

Number of tins needed by Michiko =

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b) Cost of one tin of metal paint = $8.49

∴ cost of 18 tins of paint = $152.82

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

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