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2 years ago

BRAINLIEST TO CORRECT ANSWER!!! NO links as answers, or you will be reported!! (question 4)

Mathematics

1 answer:

In-s [12.5K]2 years ago

8 0

Answer:

Hello! Your answer would be, C) Divide by 2

Step-by-step explanation:

And plz don't be mean. :(

Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia

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Express 4x^-4 with a positive exponent.

Mumz [18]

Answer:

4x^-4

4(x^-2)²

4x^4

Step-by-step explanation:

sorry I am not clear about question.

6 0

2 years ago

What is the midpoint between 3.99 and 4

asambeis [7]

Answer:

3.995

Step-by-step explanation:

A midpoint is defined as a point that is exactly in the middle between two other points. The midpoint between two numbers is the number exactly in the middle of the two numbers. Calculating the midpoint is the same thing as calculating the average of two numbers. Therefore, you can calculate the midpoint between any two numbers by adding them together and dividing by two.

6 0

2 years ago

Let g(x) = 2x2 - 11x. Find g(-1). A) -13 Eliminate B) -9 C) 0 D) 13

worty [1.4K]

Solution

g(x) = 2 $x^{2}$ - 11x

Plugging in x = -1 in g(x), we get

g(-1) = 2 $(-1)^{2}$ - 11(-1)

Now we have to simplify it.

g(-1) = 2*1 + 11

g(-1) = 2 + 11

g(-1) = 13

So the answer is D) 13.

Thank you. :)

3 0

2 years ago

What is the volume of this prism ???

pshichka [43]

Answer:

Step-by-step explanation:

6 0

2 years ago

Anyone knows how to do questions 7 and 8? 15 pts!!

Oksi-84 [34.3K]

7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: $2x^2-4x+5$ . With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

$E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3$

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

$2x^2+5=4x\\\\ 2x^2-4x+5=0$

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

$E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)$

Multiplying by (2-1) in the both sides:

$(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ...$ Repeating the process, we obtain: $...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}$

3 0

3 years ago

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