What is the Sum? -2

How to find average value of a function over a given interval?

Strike441 [17]

f(x)=8x−6f(x)=8x-6 , [0,3][0,3]

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.(−∞,∞)(-∞,∞){x|x∈R}{x|x∈ℝ}f(x)f(x) is continuous on [0,3][0,3].f(x)f(x) is continuousThe average value of function ff over the interval [a,b][a,b] is defined as A(x)=1b−a∫baf(x)dxA(x)=1b-a∫abf(x)dx.A(x)=1b−a∫baf(x)dxA(x)=1b-a∫abf(x)dxSubstitute the actual values into the formula for the average value of a function.A(x)=13−0(∫308x−6dx)A(x)=13-0(∫038x-6dx)Since integration is linear, the integral of 8x−68x-6 with respect to xx is ∫308xdx+∫30−6dx∫038xdx+∫03-6dx.A(x)=13−0(∫308xdx+∫30−6dx)A(x)=13-0(∫038xdx+∫03-6dx)Since 88 is constant with respect to xx, the integral of 8x8x with respect to xx is 8∫30xdx8∫03xdx.A(x)=13−0(8∫30xdx+∫30−6dx)A(x)=13-0(8∫03xdx+∫03-6dx)By the Power Rule, the integral of xx with respect to xx is 12x212x2.A(x)=13−0(8(12x2]30)+∫30−6dx)

3 0

4 years ago

What is the equation of the line that passes through (-5, -1) and is parallel to the line y=4x-6?

mr_godi [17]

Hello :
the equation all lines passes through (-5, -1) is :
y - (-1) = m(x -(-5)) m the slope
if this line parallal to the line y=4x-6 so : m= 4 (same slope )
the equation of the line that passes through (-5, -1) and is parallel to the line y=4x-6: is :
 y+1 =4(x+5)
y = 4x +19

8 0

3 years ago

which of the following is the equation of a line that passes through the point (3,2) and is pararell to the y-axsis

lidiya [134]

Answer:X would be 2 so The answer is c

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If the cost of a dozen eggs rises from .99 to 1.34 what is the percent of the increase

Amiraneli [1.4K]

To find the percent of increase get the difference between the prices and then divided by the oringinal price and then time that by 100

increase = $\frac{1.34 - .99}{.99} \times 100$

8 0

4 years ago

How do you solve these?

Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 = 2*2*2 *2 * 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = - 3 * 3 * 3 * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0

3 years ago

What is the Sum? -2 - (-0.7)=