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Temka [501]
3 years ago
7

You mix 1 3/4 gallons of blue paint with 1 1/2 gallons of yellow paint to make green paint. How much green paint do you have?

Mathematics
1 answer:
irakobra [83]3 years ago
3 0
IS this blaise weiss and yeuh I think its about 30 feet
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An ice cream shop owner wants to find out what new flavor of ice cream he should sell in his shop. Which method would be the BES
Genrish500 [490]
 i do believe the first one is D but im not sure about the 2nd  <span />
4 0
3 years ago
Consider the series 3/2 + 3/4 + 3/8 + 3/16 + ... What expression defines Sn?
snow_lady [41]

For the series 3/2 + 3/4 + 3/8 + 3/16 + ...the sum will be calculated by the formula  3(\dfrac{1}{2})^n.

<h3>What is number series?</h3>

When the numbers are arranged in a series with some logic then it is called as the number series.

here we have a series:

\dfrac{3}{2}+\dfrac{3}{4}+\dfrac{3}{8}+\dfrac{3}{16}+............

The sum of the series will be given as:

S_n=3(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+............)

S_n=3 (\dfrac{1}{2})^n

Hence for the series 3/2 + 3/4 + 3/8 + 3/16 + ...the sum will be calculated by the formula  3(\dfrac{1}{2})^n

To know more about number series follow

brainly.com/question/6561461

#SPJ1

5 0
2 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
50 POINTS, HELP
vazorg [7]

Answer:

a(n) = -351+8(n-1)

Step-by-step explanation:

This is an arithmetic sequence.  Each new term is equal to the sum of the previous term and 8.

The expression you want is   a(n) = -351+8(n-1)

8 0
3 years ago
Read 2 more answers
I am very stupid, can someone help me out on this one?
Alexxx [7]

Answer:

Hey these pictures can help you!

Step-by-step explanation:

8 0
3 years ago
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