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3 years ago

Whats the answer for this question

Mathematics

2 answers:

dezoksy [38]3 years ago

8 0

Answer:

0.00939495805 about 0.01

Step-by-step explanation:

basically solving for arccos(8.5/9.9) in degrees, had to run through calculator

Afina-wow [57]3 years ago

5 0

So you would use SOH-CAH-TOA and you get cos so enter cos(x)= 8.5 Once you enter this into the calc You should get 30.8
———
9.9

Answer: 31 degrees

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SOMEONE, PLEASE ANSWER THIS!

IrinaVladis [17]

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6

This cannot be simplified any more than what it is now.

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2 years ago

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What will be the sign of the product if we multiply together.

SOVA2 [1]

Answer:

(a)positive

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3 years ago

Carlos collects 26 stamps. Adam collects 38 more than Carlos. How many stamps do they have all together?

S_A_V [24]

Answer:

90 stamps

Step-by-step explanation:

We can solve this by writing an equation.

(38+26)+26

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3 years ago

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-5/3 is greater or less than square root of 3

inessss [21]

Answer:

-5/3 is less than (<) square root of 3

Step-by-step explanation:

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Hope this helps!

3 0

4 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago