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3 years ago

Explain the force that keep the rock balanced on its tiny pedestal

1 answer:

5 0

A pedestal rock, also known as a rock pedestal or mushroom rock, is not a true balancing rock, but is a single continuous rock form with a very small base leading up to a much larger crown. Some of these formations are called balancing rocks because of their appearance. The undercut base was attributed for many years to simple wind abrasion, but is now believed to result from a combination of wind and enhanced chemical weathering at the base where moisture would be retained longest. Some pedestal rocks sitting on taller spire formations are known as hoodoos. I think this is the answer if I’m wrong I’m very sorry

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As I drink my coffee, I can feel the warmth sliding down my throat and taste the deliciousness of the drink. How can that be pos

Goshia [24]

ANSWER:

drinking a lot of caffeine can cause hallucinations, but for this question its neurotransmitters

neurotransmitters send signals to the nerve cells indicating that the liquid is hot and delicious.

so your answer is D

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7 0

3 years ago

Read 2 more answers

A toy train is traveling along a circular track

Molodets [167]

Answer:

0.25 m

Explanation:

a = v² / r

4.0 m/s² = (1.0 m/s)² / r

r = 0.25 m

3 0

3 years ago

How far will a car travel in 25 seconds at 10m/ min

Kryger [21]

Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s

distance = speed × time
= 25 × (1/6)
=4.167m

7 0

4 years ago

What happens to the pressure of a gas when the volume of its container is increased at constant temperature?

zepelin [54]

<h2>Pressure decreases as volume increases at constant temperature.</h2>

Hope it helps...

Good luck on your assignment

3 0

3 years ago

Mary is an avid game show fan and one of the contestants on a popular game show. She spins the wheel, and after 5.5 revolutions,

spin [16.1K]

Answer:

The angle is 23.2 radians, equivalent to 3.69 revolutions.

Explanation:

First, we need to find the angular acceleration of the wheel. This can be done using one of the kinematic formulas:

$\omega^{2}=\omega_0^{2}+2\alpha\theta\\\\\implies \alpha=\frac{\omega^{2}-\omega_0^{2}}{2\theta}$

Since the final angular velocity is zero after 5.5 revolutions (equivalent to 11π radians) we have that:

$\alpha=\frac{-(3.15rad/s)^{2}}{2(11\pi rad)}\\\\\alpha=-0.144rad/s^{2}$

Now, using the same equation, we can solve for the requested angle:

$\theta=\frac{\omega^{2}-\omega_0^{2}}{2\alpha}\\\\\theta=\frac{(1.80rad/s)^{2}-(3.15rad/s)^{2}}{2(-0.144rad/s^{2})}\\\\\theta=23.2rad$

Finally, it means that the angle through which the wheel has turned when the angular speed reaches 1.80 rad/s is 23.2 radians, equivalent to 3.69 revolutions.

8 0

3 years ago