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3 years ago

10

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular

circuit?

1 answer:

lubasha [3.4K]3 years ago

8 0

Voltage, V = IR

Where I is current in Ampere, R is Resistance in Ohms.

V = 9A * 43 Ω

V = 387 V

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2 years ago

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And the momentum $p_{2}$ of the ping-pong ball is:

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Isolating $V_{2}$ :

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