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shepuryov [24]
4 years ago
10

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular

circuit?
Physics
1 answer:
lubasha [3.4K]4 years ago
8 0

Voltage, V = IR

Where I is current in Ampere, R is Resistance in Ohms.

V = 9A * 43 Ω

V = 387 V

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A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on th
Serhud [2]

The initial momentum of the yellow and the orange train is 1000kgm/s.

Momentum is the product of the mass and velocity of any object.

Momentum is denoted by P.

Momentum P = mv , where m = mass and v = velocity.

<h3>Given:</h3>

Mass of the orange train = 200kg

Velocity of the orange train = 1m/s

So, the momentum of the orange train will be,

                            ∴    P = mv

                                  P = 200 x 1

                                  P = 200 kgm/s

∴   The initial momentum of the orange train is 200kgm/s.

Mass of the yellow train = 100kg

Velocity of the yellow train = 8m/s

So, the momentum of the yellow train will be,

                            ∴    P = mv

                                  P = 100 x 8

                                  P = 800 kgm/s

∴ The initial momentum of the yellow train is 800kgm/s.

Therefore, the initial momentum of the yellow and the orange train is 1000kgm/s.

Learn more about momentum here:

brainly.com/question/25849204

#SPJ1

5 0
2 years ago
A 45-mH inductor is connected in series with a 60-Ω resistor through a 15-V dc power supply and a switch. If the switch is close
egoroff_w [7]

Answer:

The current is 0.248 A

Explanation:

Given that,

Inductor L= 45\times10^{3}\ H

Resistance R= 60\Omega

Voltage = 15 volt

Time t =7.0\times10^{-3}\ sec

We need to calculate the current

Using formula of current

I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)

Where, V = voltage

R = resistance

L = inductance

T = time

Put the value into the formula

I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})

I=0.248\ A

Hence, The current is 0.248 A.

4 0
3 years ago
5. Find the velocity of a train that traveled 75 km in 35 minutes. (answer
iogann1982 [59]

75km=75000m

35min=2100 seconds

Velocity=Displacement/Time

=75000/2100

=750/21

=35.71 m/s

3 0
2 years ago
The law of conservation of energy states that energy cannot be BLANK or destroyed.
Morgarella [4.7K]
Energy cannot be CREATED or destroyed, just changed or moved.
4 0
3 years ago
Read 2 more answers
Car A has a mass of 1,000 kg and is traveling 60 km/hr. Car B has a mass of 2,000 kg and is traveling 30 km/hr. Compare the kine
Artyom0805 [142]

Answer:

c) Twice as much

Explanation:

As we know that kinetic energy is given by the formula

K = \frac{1}{2}mv^2

here we know that

m = mass of the object

v = speed of the object

so here we will have kinetic energy of Car A

K = \frac{1}{2}(1000)(60^2)

K_a = 1.8 \times 10^6

now we have kinetic energy of B is given as

K_b = \frac{1}{2}(2000)(30^2)

K_b = 0.9 \times 10^6

So kinetic energy of Car A is double that of Kinetic energy of car B

3 0
4 years ago
Read 2 more answers
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