Question

A stone with a mass of 0.700kg is attached to one end of a string 0.600m long. The string will break if its tension exceeds 65.0N . The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed.
Find the maximum speed the stone can attain without breaking the string? m/s

Answer 1

Answer:v=7.46 m/s

Explanation:

Given

mass of stone=0.7 kg

Length of string=0.6 m

Maximum tension in string T=65 N

Tension will Provide centripetal force i.e. $\frac{mv^2}{r}$

$T=\frac{mv^2}{r}$

$65=\frac{0.7\times v^2}{0.6}$

$65\times 0.6=0.7\times v^2$

$v^2=\frac{65\times 0.6}{0.7}$

$v^2=55.71$

$v=\sqrt{55.71}=7.46 m/s$