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Inga [223]
3 years ago
10

at a concert, 2/5 of the people were men.there were 3 times as many women as children. if there were 45 more men than children h

ow many people were at the concert
Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0
People: p 
<span>men: 2/5 p </span>
<span>children: c </span>
<span>women: 3c </span>
<span>men: 2/5 p = c+45 </span>
<span>people = m+w+c = 2/5 p + 3c + c </span>

<span>so, p = 2/5 p + 4c </span>

<span>3/5 p = 4c </span>
<span>2/5 p = c+45 </span>

<span>c=27 </span>
<span>p=180 </span>
<span>180 people at the show. </span>

<span>so, women=81 </span>
<span>men=72 </span>
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Jeremy bakes two pans of brownies that are the same size. One pan has nuts in it and the other pan does not. He cuts the pan wit
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Answer:

The answer is "\frac{2}{8} > \frac{3}{16} So, they eat more brownies with nuts".

Step-by-step explanation:

In the given question, the two browny pans of equal size are baked by Jeremy. There is indeed a saucepan with nuts in it, not the other pan. He split the pot into eight equal chunks with nuts. He slices the pan into 16 equal parts without nuts. His mates eat 2 nuts brownies and three nut-free brownies. They eat more nuts and brownies \frac{2}{8} > \frac{3}{16} eat more.

5 0
3 years ago
Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye
Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let \rho(x,y) be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

m=\int\limits \int\limits_D \rho(x,y) \, dA.

From the question, the given density function is \rho (x,y)=xye^{x+y}.

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx.

Since D is a rectangular region, we can apply Fubini's Theorem to get:

I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx.

Let the inner integral be: I_0=\int\limits^1_0xye^{x+y}dy, then

I=\int\limits^1_0(I_0)dx.

The inner integral is evaluated using integration by parts.

Let u=xy, the partial derivative of u wrt y is

\implies du=xdy

and

dv=\int\limits e^{x+y} dy, integrating wrt y, we obtain

v=\int\limits e^{x+y}

Recall the integration by parts formula:\int\limits udv=uv- \int\limits vdu

This implies that:

\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy

\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}

I_0=\int\limits^1_0 xye^{x+y}dy

We substitute the limits of integration and evaluate to get:

I_0=xe^x

This implies that:

I=\int\limits^1_0(xe^x)dx.

Or

I=\int\limits^1_0xe^xdx.

We again apply integration by parts formula to get:

\int\limits xe^xdx=e^x(x-1).

I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1).

I=\int\limits^1_0xe^xdx=0-1(0-1).

I=\int\limits^1_0xe^xdx=0-1(-1)=1.

No unit is given, therefore the mass of the lamina is 1.

3 0
3 years ago
What is the surface area of the cylinder?
Murrr4er [49]
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3 years ago
(answer ASAP! thanks.) "As part of a math project, Joel recorded the types of vehicles passing an intersection in one hour. His
ANTONII [103]

Step-by-step explanation:

There is a total amount of vehicle of 100

which is good because now you can say 73% is cars 16% is small trucks 6% is large trucks and 2% motorcycle and 3% bicycle. Adding the trucks (small 16, large 6) gives us 24% so you can do 100% - 24% and get 74%. Thanks and goodbye!

7 0
3 years ago
Please help! With steps included :)
Len [333]

Answer:

Top question: -7°

Bottom question : 18°

Step-by-step explanation:

Top question:

The base angles of am isosceles triangle are congruent:

x + 46 = 39 because the base angles of an isosceles triangle are congruent

x + 46° = 39°

x = -7°

Bottom question

The missing angle is 3x because the base angles are congruent

To find the value of x, we must add all the angles inside the triangle, and find the value of x that makes it equal to 180°

3x + 3x + 4x = 180°

10x = 180°

x = 18°

Sorry for the late post!

-Chetan K

8 0
3 years ago
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