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frosja888 [35]
3 years ago
14

Express the fractions as equivalent decimals.5/25

Mathematics
2 answers:
Svetach [21]3 years ago
6 0

Answer:

th5

Step-by-step explanation:

e answer is 5

udeeeeee5t is the most

zepelin [54]3 years ago
3 0

Answer:

0.2

Step-by-step explanation:

5 divided by 5 is 1

25 divided by 5 is 5

1/5 is the same as 1 divded by 5

=0.02

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Franco has $265.87 in his checking account. Then he writes the deposit slip shown. How should Franco enter the deposit in his ch
artcher [175]

Answer:

The answer is the top right one since the total $96.35 is on the deposit side.

( i did this before and got it right btw)

8 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Which number is between 5/2 and the square root of 11
Andrei [34K]
3 hoped that helped you
4 0
3 years ago
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If i bike travels 15m in 2 sec, what is its speen in km/h?
shutvik [7]

Answer:

x=27 km

Step-by-step explanation:

Make an equation 2/.015=3600/x

Multiply 3600 by .015 to get 54

Divide 54 by 2 to get 27.

3 0
3 years ago
Read 2 more answers
if each dimension of a unit cube is increased by 1. what is the ratio between the surface area of the new cube to that of the or
nexus9112 [7]

Answer:

4:1 or 4/1

Step-by-step explanation:

Original surface area: Each side is 1 * 1 = 1 and there are 6 sides, so 1 * 6 = 6.

New surface area: Each side is 2*2 = 4, and there are 6 sides, so 4 * 6 = 24

The ratio would be 24:6, or 4:1. As a fraction, this would be 4/1

4 0
3 years ago
Read 2 more answers
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