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vesna_86 [32]
4 years ago
13

An earth observer sees an alien ship pass overhead at 0.3c. The ion gun of the alien ship shoots ions straight ahead of the ship

at a speed 0.4c relative to the ship. What is the speed of the ions relative to the earth observer?
Physics
1 answer:
hoa [83]4 years ago
6 0

Answer:

The velocity of the ions relative to the earth observer is  v = 0.63 c

Explanation:

From the question  we are told that

     The speed of the alien ship is  v_a  = 0.3c

     The speed of the iron gun is  v_g  =  0.4c

The motion of the ions  relative to the earths observer can be mathematically represented as

       v  =  \frac{v_a + v_g}{[\frac{1+ v_av_g}{c^2} ]}

substituting values

     v  =  \frac{ 0.3c + 0.4c}{[\frac{1+ 0.3c * 0.4c}{c^2} ]}

 =>   v = 0.63 c

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Answer:

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Explanation:

Here is the complete question.

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b) Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below.  

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a. Since she lands 8.2 m away and leaves at an angle of 45 above the horizontal, this is a case of projectile motion. We calculate the takeoff speed v₀ from R = v₀²sin2θ/g. where R = range = 8.2 m.

So, v₀ = √gR/sin2θ = √9.8 × 8.2/sin(2×45) = √80.36/sin90 = √80.36 = 8.96 m/s.

b. We use R = v₀²sin2θ/g to calculate how long or short of the opposite bank she will land. With v₀ = 8.96 m/s and θ = 45

R = 8.96²sin(2 × 45)/9.8 = 80.2816/9.8 = 8.192 m.

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