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vesna_86 [32]
4 years ago
13

An earth observer sees an alien ship pass overhead at 0.3c. The ion gun of the alien ship shoots ions straight ahead of the ship

at a speed 0.4c relative to the ship. What is the speed of the ions relative to the earth observer?
Physics
1 answer:
hoa [83]4 years ago
6 0

Answer:

The velocity of the ions relative to the earth observer is  v = 0.63 c

Explanation:

From the question  we are told that

     The speed of the alien ship is  v_a  = 0.3c

     The speed of the iron gun is  v_g  =  0.4c

The motion of the ions  relative to the earths observer can be mathematically represented as

       v  =  \frac{v_a + v_g}{[\frac{1+ v_av_g}{c^2} ]}

substituting values

     v  =  \frac{ 0.3c + 0.4c}{[\frac{1+ 0.3c * 0.4c}{c^2} ]}

 =>   v = 0.63 c

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Alex_Xolod [135]

Answer:

\theta_2 = 15.8degree

Explanation:

given data:

\theta_1 = 28.7 degree

accoding to the snell's law

n_1*sin\theta_1=n_2*sin\theta_2

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putting all value to get angle mad by incident ray with normal

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\theta_2 = 15.8degree

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Answer:

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