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vampirchik [111]
3 years ago
7

While teaching about transistors, Mr. Mendoza shows a video of a hand pump being used to draw water from a well. He points out h

ow the person primes the pump by pouring a small amount of water into it before the water would start to flow. No matter how much water is used to prime the pump, once started, the pump provides a steady flow of water while the handle is operated.
What is Mr. Mendoza using the hand pump to model?

A. its use as a switch to make a small signal into a large signal
B. its use as an amplifier to make a small signal into a large signal
C. its use as a switch to turn on a large current using a small current
D. its use as an amplifier to turn on a large current using a small current
Physics
2 answers:
Alchen [17]3 years ago
5 0

Answer:

The answer is B,  Mr Mendoza is using the hand pump to model an amplifier to make a small signal into a large signal.

Explanation:

An amplifier basically is an electronic gadget used to cover lower signal or current  input into higher current, signal or output. In a situation where water is being pumped into a reservoir and the level of the reservoir is higher than that of the well, am amplifier can used used with the pump to increase the output current going into the pump thereby increase the speed and flow of water into the reservoir.

storchak [24]3 years ago
5 0

Answer:

B

Explanation:

Transistors are small pieces of semiconductor electronic devices that are used basically for amplification and switching of signals.

They are used to amplify a small signal to a larger one.

They function as switches as they determine if current flows through the collector emitter path. When a voltage is applied to the base it allows currents to flow through to C-E path, but if no current is applied no current will flow .

In the illustration given in the question the pump provides a steady flow of water when a small quantity of water is fed into it. This can be compared to the use of transistors as an amplifier in converting small signals into large signals.

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Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

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Explanation:

From the question we are told that

     The time  constant  \tau  =  3

The potential across the capacitor can be mathematically represented as

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   Generally energy stored in a capacitor is mathematically represented as

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Now  since capacitance is  constant  at  \tau  =  3

        The  energy stored can be evaluated at as

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       V^2 =  0.903  V_o ^2

Hence the fraction of the energy stored in an initially uncharged capacitor is  

      k  = 0.903

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