Answer: Really
Explanation:
Just look it up for this page and maybe you will find an anwser sheet.
Part A: a->positive when velocity is increasing a->negative when velocity is decreasing a->zero when velocity is constant
Given :
Whole-body dose of 8.4 mGy from gamma-rays and 1.2 mGy from 80-Kev neutrons.
To Find :
The effective dose to a worker.
Solution :
By the given information effective dose to a worker is given by :
E.D = ( 8.4 × 1.2 × 0.12 ) + ( 1.2 × 1 × 1 )
E.D = 1.2096 + 1.2
E.D = 2.4096
Therefore, the effective dose to a worker is 2.4096 .
Answer:
a. 2.53 μJ b. It will move away
Explanation:
a. What is the electric potential energy between the particles?
The electric potential energy U = kq₁q₂/r where k = 9 × 10⁹ Nm²/C², q₁ = 4.1 nC = 4.1 × 10⁻⁹ C, q₂ = 2.4 nC = 2.4 × 10⁻⁹ C and r = distance between charges = 3.5 cm = 3.5 × 10⁻² m.
Substituting the values of the variables into U, we have
U = kq₁q₂/r²
U = 9 × 10⁹ Nm²/C² × 4.1 × 10⁻⁹ C × 2.4 × 10⁻⁹ C/3.5 × 10⁻² m
U = 88.56 × 10⁻⁹ Nm²/3.5 × 10⁻² m
U = 25.3 × 10⁻⁷ Nm
U = 2.53 × 10⁻⁶ Nm
U = 2.53 × 10⁻⁶ J
U = 2.53 μJ
b. And if the second particle is released will it move forward or away from the source charge.
It will move away from the source charge since they have the same sign of charge. Since, opposite charges repel.