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ioda
3 years ago
11

A dart gun shoots a dart with an angle of 45' above horizontal During the upward part of the trajectory the gravitational accele

ration g is directed 1 Upward and ts value changes with height 2 Upward and its value changes with height 3 There is no accelaration 4 Downward and its value is constant 5 Downward and ts value changes with height
Physics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

4. Downward and its value is constant

Explanation:

As this is a case of projectile motion, we use the reference frame where upward direction to be positive for y, and in the same way to be negative in the downward direction. On another hand, we have that gravity is always acting this means that gravitational acceleration g is directed downward constantly over the dart not only during the upward but also during the downward part of the trajectory. And it is ruled by the following equations.

For the x-axis

v_{x}=v_{0}cos(45\°)=constant

x=(v_{0}cos(45\°))t

For the y-axis

v_{y}=v_{0}sin(45\°)-gt

y=v_{0}sin(45\°)t-\frac{1}{2} gt^{2}

Where v_{0}, is the initial velocity.

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What is the effective dose to a worker who receives uniform, whole-body dose of 8.4 mGy from gamma-rays and 1.2 mGy from 80-Kev
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A fixed source charge particle of 4.1 nC and a second particle with a charge 2.4 nC are separated by a distance of 3.5 cm. What
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Answer:

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The electric potential energy U = kq₁q₂/r where k = 9 × 10⁹ Nm²/C², q₁ = 4.1 nC = 4.1 × 10⁻⁹ C, q₂ = 2.4 nC = 2.4 × 10⁻⁹ C and r = distance between charges = 3.5 cm = 3.5 × 10⁻² m.

Substituting the values of the variables into U, we have

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U = 2.53  μJ

b. And if the second particle is released will it move forward or away from the source charge.

It will move away from the source charge since they have the same sign of charge. Since, opposite charges repel.

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3 years ago
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