Question

What is 4^2y-3^2=-5y+(-5+7) Please explain step by step i need this asap :/

Answer 1

$4^2y-3^2=-5y+(-5+7)$

simplify stuff by pemdas, 4^2=16, 3^2=9, -5+7=2

$16y-9=-5y+2$

add 5y to both sides

$21y-9=2$

add 9 both sides

$21y=11$

divide both sides by 21

$y=\frac{11}{21}$

Answer 2

y = 11/21

To solve this first evaluate the power (then calculate the sum):

$4^{2}$y - $3^{2}$ = 5y + (-5 + 7)

16y - 9 = -5y + 2

Next Move terms (move variable to the left side and change its sign) (Move constant to the right side and change its sign):

16y - 9 = -5y + 2

16y + 5y = 2 + 9

Next Collect the like terms and calculate the sum:

16y + 5y = 2 + 9

21y = 11

Lastly divide both sides of the equation by 21:

21y = 11

y = $\frac{11}{21}$