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3 years ago

Oliver traveled 124.25 miles in 3.5 hours at a constant speed. What is the constant of proportionality in miles per hour?

Mathematics

2 answers:

Citrus2011 [14]3 years ago

6 0

Answer:

hello, i found that the answer is C

hope this helps! have a good day

Step-by-step explanation:

Elan Coil [88]3 years ago

3 0

Answer:

Simple!

All you have to do is divide 3.5 by 124.25

124.25 / 3.5 = 35.5

Your answer is C.

Hope this helps!

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The value of which of these expressions is closest to e?

Anna [14]

Answer:

Using a calculator, we can check that e=2.718281828.

Step-by-step explanation:

Lets evaluate each one of our expression the check which one is closest to e:

(1+ \frac{1}{31} )^{31}=2.675686306

(1+ \frac{1}{32})^{32}=2.676990129

(1+ \frac{1}{34} )^{34}=2.679355428

(1+ \frac{1}{33} )^{33}=2.678207651

We can conclude that the value of (1 +1/34) to the power of 34 is the closest to the value of e.

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=0.6%20%5Csqrt%7B33.54%7D%20" id="TexFormula1" title="0.6 \sqrt{33.54} " alt="0.6 \sqrt{33.54}

ki77a [65]

$0.6\sqrt{33.54}$

$=5.79137$

$0.6*5.79137$

$=3.4$

Hope this helps!

Thanks!

-Charlie

6 0

3 years ago

How to solve these question

mamaluj [8]

Number 3 answer is 11n/4

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3 years ago

Right triangle DEF is shown.

KatRina [158]

Answer:

Step-by-step explanation:

5 0

3 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

3 years ago

Read 2 more answers