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Neporo4naja [7]
3 years ago
5

Find the midpoint of AC if A is located at (-4,9) and C is located at (1,31)

Mathematics
1 answer:
aliina [53]3 years ago
3 0
The midpoint of AC is (-1.5, 20)
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Find two numbers whose difference is 102 and whose product is a minimum. Step 1 If two numbers have a difference of 102, and one
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Answer:

The two numbers would be -51 and 51

Step-by-step explanation:

To find these, first set the equation for the first number as x. You can then set the second number as x + 102. Now, find their product.

x(x + 102) = x^2 + 102x

Now, to find the minimum, find the value of x in the vertex of this equation.

-b/2a = -102/2(1) = -102/2 = -51

So we know -51 is the first number. Now we find the second using the prewritten equation.

x + 102 = -51 + 102 = 51

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3 years ago
What is 23.67 times 2.03​
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23.67 X 2.03 = 48.0501

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Anyone know the answer???
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Answer:

k = 10

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

115 = (4k+5) + (6k+10)

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115 = 10k+15

Subtract 15 from each side

115-15 = 10k +15-15

100 = 10k

Divide by 10

100/10 = 10k/10

10 =k

8 0
3 years ago
A grey squirrel population was introduced in a certain county of Great Britain 35 years ago. Biologists observe that the populat
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If this occurred over a span of 35 years and the population doubles every 7 years, we can divide 35 by 7 to find how many times the population has doubled, which would be 5 times. If we divide 60,000 by 2 (or multiply by 1/2) 5 times, you would get the answer, which would be 1,875.
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sons in the NHL,nts than anyone whoccomplished thiser games thanHer. Here are theRg each season:74, 45, 81, 48, 80,Working for a
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Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}

Median = 41

\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile  = 49} \end{gathered}

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22

\begin{gathered} Q1\text{  Position = }\frac{(n+1)^{th}\text{ }}{4}\text{ = }\frac{16}{4}th=4^{th} \\ Q_1\text{ = 31} \end{gathered}

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\begin{gathered} UpperquartileQ_{_3\text{ }}\text{ = 49} \\  \end{gathered}

Maximum = 68

Interquartile range = 49 - 31 = 18

8 0
1 year ago
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