You put them in fractions then cross multiple.
18/12 and 3/x so that's 36 equals 18x then you divide 36 by 18 which is 2.
Answer:
y = 0 and x = 6
y = 2 and x = 3
y = 4 and x = 0
y = 6 and x = -3
Step-by-step explanation:
2x+3y=12 is the equation of a straight line.
There are infinite number of solutions, but here you're probably looking for solutions where x and y are whole numbers. Trial and error will find you some, although if you examine the equation closely you see that if x is a multiple of 3 and y is a multiple of 2, then they produce terms that are the LCM (least common multiple) of 2 and 3, namely 6. That's the logic in the whole number solutions.
= 6x + 6x - 6x × 7 + 6xy - 7y
36x2 - 42x + 6xy - 7y
Answer:
136
Step-by-step explanation:
The formula you use is as follows:
A=2(WL+HL+HW)
You plug in each number to get this equation
A=2[(6*7)+(2*7)+(2*6)]
A=2(42+14+12)
A=2(68)
A=136
Answer:
y=1/∛4 divides the area in half
Step-by-step explanation:
since the minimum value of x² is 0 (for x=0 ) and for y=1
1 = 25*x² → x= ±√(1/25) = ±1/5
then the total area between y=1 and y = 25*x² is bounded to x=±1/5 and y=0 . Since there is a direct relationship between x and y , we can find the value of x=a that divides the region in 2 of the same area. thus
Area below x=C = Area above x=C
Area below x=C = Total area - Area below x=C
2*Area below x=C = Total area
Area below x=C = Total area /2
∫ 25*x² dx from x=c to x=-c = 1/2 ∫ 25*x² dx from x=1/5 to x=-1/5
25*[c³/3 - (-c)³/3] = 25/2 * [(1/5)³/3 - (-1/5)³/3]
2*c³/3 = (1/5)³/3
c = 1/(5*∛2)
thus
y=25* x² = 25*[1/(5*∛2)]² = 1/∛4
thus the line y=1/∛4 divides the area in half
