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Crazy boy [7]
3 years ago
7

If 2x^2 -2y^2 = 72 and if x+y=18 what does x-y equal

Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0
First factor out the 2:

x^2 - y^2 = 36

x^2 - y^2 can be factored into (x+y)(y-y) so:

(x + y)(x - y) = 36

plug in your value:

18 (x-y) = 36 and you should be able to take it from there
Shalnov [3]3 years ago
6 0
2x^2-2y^2=72
divide both sides by 2
x^2-y^2=36
factor difference of 2 perfect squares
(x-y)(x+y)=36
given that x+y=18, subsitute 18 for x+y
(x-y)(18)=36
divide both sides by 18
x-y=2
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What is 1 5/6 + 7 3/4=
KengaRu [80]

Answer: 9 7/12


TO simplify the answer make common denominator which would be 12 so 5/6 times 2 on each 10/12 & 3/4 x3 becomes 9/12 so those make 1 7/12 add with 1 and 7

4 0
3 years ago
Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...
12345 [234]
    4x + 2y = 8     (1)
    8x + 4y = -4y  (2)

A) Two lines are parallel if they have the same gradient
       - putting both equations into the gradient- intercept form ( y = mx + c                where m is the gradient)
            (1) 4x + 2y = 8
                          2y = 8 - 4x
                            y = -2x + 4
             
            (2) 8x + 4y = -4y
      <span>                    </span>8x = -4y - 4y
                            y = \frac{-8x}{-8}
                            y = -x
   <span>Thus the gradient of the two equations are different and as such          the two lines are not parallel
</span>
B)  When two lines are perpendicular, the product of their gradient is -1
                   m_{1} * m_{2} = p
                                             p = (-2) * (-1)
                                             p =  2
<span>          ∴ the two lines are not perpendicular either.</span>

Thus these lines are SKEWED LINES

4 0
3 years ago
$570, 2%, 6 months <br> -<br> Help, I don’t get how to do it.
Phantasy [73]

Answer:

$641.91

Step-by-step explanation:

A(t) = 570(1+0.02)^6

8 0
3 years ago
The intersection of lines y=-14x+3 and y=-32x+3 is .
Kamila [148]

The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

<h3>How to determine the intersection of the lines?</h3>

The lines are given as:

y = -14x + 3 and y = -32x+3

Substitute y = -32x+3 in

-32x+3 = -14x + 3

Evaluate the like terms

-18x = 0

Divide by -18

x = 0

Substitute x = 0 in y = -14x + 3

y = -14(0) + 3

Evaluate

y = 3

Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

6 0
2 years ago
⦁ Write an equation of a line in slope intercept form (y = mx + b) with slope 1/3 going through the point (-6, 2). Show your wor
Zepler [3.9K]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y-2=\cfrac{1}{3}(x+6)\implies y-2=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+4

3 0
2 years ago
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