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3 years ago

Write this number in standard form 400,000+30,000+800+20+5

Mathematics

2 answers:

Alexus [3.1K]3 years ago

8 0

430825 acho que é esse

Arturiano [62]3 years ago

5 0

430,825 I think, correct me if I'm wrong.

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Find the area of the kite with the given information.

inessss [21]

Answer:

Area of the given kite = 84 square inches.

Step-by-step explanation:

Properties of the diagonals of a kite,

1). Diagonals are perpendicular to each other.

2). Longer diagonal bisects the smaller one.

Therefore, Length of smaller diagonal BD = 2×6 = 12"

In right ΔAEB,

m∠ABE = m∠EAB = 45°

Therefore, in isosceles triangle AEB,

AE = BE = 6"

Now the length of longer diagonal AC = AE + EC

AC = 6" + 8"

= 14"

Area of the given kite ABCD = $\frac{1}{2}(d_1)(d_2)$

= $\frac{1}{2}(AC)(BD)$

= $\frac{1}{2}(14)(12)$

= 84 square inches

3 0

3 years ago

Suppose f(x) is continuous on [2,8] and −4≤f′(x)≤5 for all x in (2,8). Use the Mean Value Theorem to estimate f(8)−f(2).

bazaltina [42]

2≤x≤8 −4≤f′(x)≤5 f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that f′(c)=f(8)−f(2)/8−2 And we know −4≤f′(c)≤5 => we have −4≤ f(8)−f(2)/8−2 ≤5

6 0

4 years ago

Find f ( - 3 ) for the function below. { ( - 3, 2 ), ( - 1, 0 ), ( 1, 1 ), ( 3, - 3 ) }

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

Question

Comment

The f(x) notation means that were ever you see n x on the right you put the value of x.

The question is which point has x = - 3 and what is the associated y value?

You could do it this way, just so you understand it.

=========================

-3 2 <======

-1 0

1 1

3 -3

The answer must be the first one

6 0

2 years ago

PLS HELP WILL MARK BRAINLIEST PLS INCLUDE SOLUTION

cluponka [151]

Answer:

11×¹ no need to worry now

8 0

3 years ago

Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.

igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

7 0

4 years ago