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AlexFokin [52]
3 years ago
6

Arithmetic sequence 5,3,1,-1 find a^18

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Arithmetic sequence  5, 3, 1, -1 then value of a^18 is 3814697265625.

<u>Solution:</u>

Given, arithmetic sequence is 5, 3, 1, -1

We have to find the value of a^{18}  

We know that, first term of any A.P is represented by the letter “a”

So, here in our problem first term a = 5

Then we have to find the value of  5^{18}

5^{18}=5^{4+4+4+4+2}=5^{4} \times 5^{4} \times 5^{4} \times 5^{4} \times 5^{2}

\text { since } a^{m+n}=a^{m} \times a^{n}

\begin{array}{l}{=625 \times 625 \times 625 \times 625 \times 25} \\\\ {=390625 \times 390625 \times 25} \\\\ {=152587890625 \times 25} \\\\ {=3814697265625}\end{array}

Hence, the value of a^18 is 3814697265625.

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Assignment: \bold{Solve \ Equation: \ 3x^2+15x=18}

<><><><><><><>

Answer: \boxed{\bold{x=1,\:x=-6}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Subtract 18 From Both Sides

\bold{3x^2+15x-18=18-18}

[ Step Two ] Simplify

\bold{3x^2+15x-18=0}

[ Step Three ] Solve With Quadratic Formula

Note: \bold{For\:a\:quadratic\:equation\:of\:the\:form\: ax^2+bx+c=0}

\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\bold{a=3,\:b=15,\:c=-18:\quad x_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}}

<><><><><><><>

\bold{\frac{-15+\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ 1}

\bold{\frac{-15-\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ -6}

[ Step Four ] Combine Solutions

\bold{x=1,\:x=-6}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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<h3>What is a local maximum/minimum?</h3>

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