I need help with number 3
1 answer:
The hexagon divides the circle into 6 parts. That means the angle projecting each side is: 360°÷ 6 = 60°
The area of a circle is: πr²
78.54 in² divided by pi is 25 making the radius = 5
I would then use SOH CAH TOA to solve for the side.. knowing the hypotenuse is the radius and the angle to split it into a right triangle is 30°
Sin(30) = s/5
5*Sin(30) = s
12*s = perimeter hexagon
(remember s is half the hexagon side)
12*5*Sin(30) = perimeter hexagon
30 inches = perimeter
The area of a circle is: πr²
78.54 in² divided by pi is 25 making the radius = 5
I would then use SOH CAH TOA to solve for the side.. knowing the hypotenuse is the radius and the angle to split it into a right triangle is 30°
Sin(30) = s/5
5*Sin(30) = s
12*s = perimeter hexagon
(remember s is half the hexagon side)
12*5*Sin(30) = perimeter hexagon
30 inches = perimeter
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Answer:
{x∈R | , x∉Z}
Step-by-step explanation:
Given the function y=3tan(2/3x)
We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers
Also, the roots of y=3tan(2/3x) is where n is an integer
Note that the domain of the function cannot be within
Therefore, {x∈R | , x∉Z}