Answer:
2 yards.
Step-by-step explanation:
If you do what was stated in the problem, you would be left at -2. So, you would need to move up 2 yards to get back to 0.
Answer:
1.60
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area =
So that,
for the inner part of the pipe,
r =
=
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r =
= 2.6 feet
Area of the pipe =
= 3.14 x
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .
(64)^3/2 = (sqrt(64))^3 = 8^3 = 512.
Answer:
<h2>6÷4(7+8) </h2><h2>= 22,5</h2>
<h2>8-6(4+9)</h2><h2>= 26</h2>
<h2>4÷8(9+3)</h2><h2>= 6</h2>
Step-by-step explanation:
<h2>6÷4(7+8)</h2><h3>= 6÷4(15)</h3><h3>= 1,5 × 15</h3><h3>= 22,5</h3>
<h2>8-6(4+9)</h2><h3>= 8-6(13)</h3><h3>= 2 × 13</h3><h3>= 26 </h3>
<h2>4÷8(9+3)</h2><h3>= 4÷8(12)</h3><h3>= 0,5 × 12</h3><h3>= 6</h3>
X is -4 Isolate the variable by dividing each side by factors that don't contain the variable.