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3 years ago

7

The length of a rectangle is 2/5 its width and the perimeter is 280 inches, what are the length and width of the rectangle?

1 answer:

bogdanovich [222]3 years ago

6 0

If the length is 2/5, or .40, then:

280/.40= 700

Check my answer:

.40*700= 280

The length is .40 (or 2/5) the width is 700.

I hope this helped!

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marissa [1.9K]

Answer:

200 trucks

Step-by-step explanation:

There's about 15 trucks in the 2nd row from the right. It looks to be about 1/2 the size of the rows to the left of it.

So based on that, I can assume, there are about 30 trucks in each of the 5 long rows, and both of the short rows would make up about another 30 trucks total. There are various trucks parked along the perimeter or between rows, so I estimated there would be about 20 of those based on 3 per row.

30 x 5 = 150 +30 = 180 + 20 = 200

3 0

2 years ago

A bed & bath company intends to ship out 28,457 blue blankets, and three times as many white blankets. If each box contains

Butoxors [25]

28457 x 3 = 85371 white blankets

85371 + 28457 = 113,828 total blankets

113828/55 = 2069.6 total boxes

so 2069 full boxes

and 55*.6 = 33 left over blankets

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2 years ago

Please help ASAP!!!!!

HACTEHA [7]

It’s D, y = 4.
have a good day :)

6 0

3 years ago

Read 2 more answers

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

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2 years ago

HELP ONE QUESTION <br> I WILL CROWN BRAINLIEST!!

Daniel [21]

Answer:

In the picture I send above shows the step by step how to get the answers. Cheers!

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2 years ago