All categories

2 years ago

Alvin's age is two times Elga's age. The sum of their ages is 84 . What is Elga's age?

Mathematics

1 answer:

son4ous [18]2 years ago

6 0

Alvin's age + Elga's age = 84
2R + R = 84
3 R = 84
3/ 3 R = 84/ 3
R = 28
Elga's age is 28

You might be interested in

A) y= 3x + 10<br> B) y= 3x + 60<br> C) y= 4x + 5<br> D) y= 4x + 35

Afina-wow [57]

Answer:

d or a

Step-by-step explanation:

50/55/100/105/.................

6 0

2 years ago

Describe a situation that is defined by the linear equation P = 40 + 22t.

sashaice [31]

The situation that is defined by the linear equation P = 40 + 22t is "The initial amount is 40 and the rate of change is 22".

<h3>What is a linear equation?</h3>

Given:

P = 40 + 22t

where,

P = total price
40 = initial amount
22 = rate of change
t = number of rate of change

So,

if t = 3

P = 40 + 22t

= 40 + 22(3)

= 40 + 66

P = 106

Therefore, the initial amount is 40 and the rate of change is 22 describes the linear equation P = 40 + 22t

Learn more about linear equation:

brainly.com/question/14323743

4 0

2 years ago

Please help I’ll mark brainliest! Thank you and have a great day/night!

Lera25 [3.4K]

Answer:

-10

Step-by-step explanation:

You always want to solve the inner function first.

g(-2)=(-2)³+3

=-8+3

=-5

g(-2)=-5 so you can replace g(-2) with -5

Now you just have f(-5)

Solve.

f(-5)=-5-5

f(-5)=-10

7 0

2 years ago

2+2-2-5+5+6+4+8-2+47+28

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

So, you basically basic math it, or calculator.

5 0

2 years ago

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fen

baherus [9]

Answer:

Area = 2500 square feet is the largest area enclosed

Step-by-step explanation:

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing

Let x be the length of each box and y be the width of the box

Perimeter of the box= 3(length ) + 4(width)

$200=3x+4y$

solve for y

$200=3x+4y$

$200-3x=4y$

divide both sides by 4

$y=50-\frac{3x}{4}$

Area of the rectangle = length times width

$Area = 3x \cdot y$

$Area = 3x \cdot (50-\frac{3x}{4})$

$A=150x-\frac{9x^2}{4}$

Now take derivative

$A'=150-\frac{9x}{2}$

Set it =0 and solve for x

$0=150-\frac{9x}{2}$

$150=\frac{9x}{2}$

multiply both sides by 2/9

$x=\frac{100}{3}$

$A''=-\frac{9}{2}$

For any value of x, second derivative is negative

So maximum at x= 100/3

$A=150x-\frac{9x^2}{4}$ , replace the value of x

$A=150(\frac{100}{3})-\frac{9(\frac{100}{3})^2}{4})$

Area = 2500 square feet is the largest area enclosed

3 0

2 years ago