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3 years ago

9

Mae earns a weekly salary of $330 plus a commission of 6.0% on a sales gift shop.How much would she make if she sold $4300 worth

of merchandise?

1 answer:

likoan [24]3 years ago

7 0

Answer:

Total income = $588

Step-by-step explanation:

Given:

Weekly salary = $330

Commission = 6%

Total sales = $4,300

Find:

Total income

Computation:

Total commission = $4,300 x 6%

Total commission = $258

Total income = Weekly salary + Total commission

Total income = $330 + $258

Total income = $588

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Directions: Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).. Th

Anuta_ua [19.1K]

Answer

Find out the The numerical value of A - B and the numerical value of B - A .

To prove

As given

The expression 113.47 - (43.72 - 26.9) represents A.

The expression 113.47 - (26.9 - 43.72) represents B .

Thus

A - B = 113.47 - (43.72 - 26.9) - ( 113.47 - (26.9 - 43.72))

First solving the bracket terms.

A - B = 113.47 - (43.72 - 26.9) - 113.47 + (26.9 - 43.72)

= 113.47 - 16.82 - 113.47 - 16.82

= 113.47 - 113.47 - 16.82 - 16.82

= -33.64

Therefore the value of A- B is -33.64 .

Thus

B - A = 113.47 - (26.9 - 43.72) - (113.47 - (43.72 - 26.9))

First solving the bracket terms.

B - A = 113.47 - (26.9 - 43.72) - 113.47 + (43.72 - 26.9)

= 113.47 + 16.82 - 113.47 + 16.82

= 33.64

Therefore the value of the A - B is -33.64 and B - A is 33.64 .

6 0

3 years ago

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Pepsi [2]

Answer:

A is the answer

Step-by-step explanation:

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3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

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3 years ago

Can someone help with this<br> Simplify: 9^-3

saw5 [17]

Note that a^-3 = 1/a^3
9^3 = 729
1/9^3 = 1/729
Solution: 1/729

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3 years ago

EXAMPLE 10 Show that there is a root of the equation 2x3 − 4x2 + 3x − 2 = 0 between 1 and 2. SOLUTION Let f(x) = 2x3 − 4x2 + 3x

muminat

Answer: $c = 1.2$

Step-by-step explanation:

First, it is needed to determined the values for x = 1 and x = 2:

$f(1) = -1, f(2)=4$

The sign change within the interval is the most sound evidence of the root existence. According to the Intermediate Value Theorem, there is a number $c$ such that $f(c) = 0$ . Another finding is that $c$ is closer to 1 than to 2.

$c = a + \frac{b-a}{f(b)-f(a)}\cdot[f(c)-f(a)]$

$c = 1 + \frac{2-1}{4-(-1)}\cdot[0-(-1)] \\c = 1.2$

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3 years ago