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Varvara68 [4.7K]
3 years ago
6

Urgentttt please❤️ Urgent

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer: a = 110ᴼ

Step-by-step explanation:

The angles on each line of the figure add to equal 180ᴼ

180 - 70 = 110

a = 110ᴼ

b and 70ᴼ are vertical angles, so their measures are congruent.

b = 70ᴼ

180 - 70 = 110

c = 110ᴼ

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Find the squares of (y+3)​
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(y-3)^2=y^2+(2×-3×y)+9

=y^2-6y+9

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2

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Will mark Brainlest please answer. find the value of a,b. <br>,p,q from the equal order pairs​
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Step-by-step explanation:

<h3>Question-1:</h3>

by order pair we obtain:

\displaystyle  \begin{cases}   \displaystyle 3p = 2p - 1 \dots \dots i\\2q - p =  1 \dots  \dots ii\end{cases}

cancel 2p from the i equation to get a certain value of p:

\displaystyle  \begin{cases}   \displaystyle p =  - 1 \\2q - p =  1 \end{cases}

now substitute the value of p to the second equation:

\displaystyle  \begin{cases}   \displaystyle p =  - 1 \\2q - ( - 1) =  1 \end{cases}

simplify parentheses:

\displaystyle  \begin{cases}   \displaystyle p =  - 1 \\2q  +  1=  1 \end{cases}

cancel 1 from both sides:

\displaystyle  \begin{cases}   \displaystyle p =  - 1 \\2q  =  0\end{cases}

divide both sides by 2:

\displaystyle  \begin{cases}   \displaystyle p =  - 1 \\q  =  0\end{cases}

<h3>question-2:</h3>

by order pair we obtain:

\displaystyle  \begin{cases}   \displaystyle 2x - y= 3 \dots \dots i\\3y= x + y \dots  \dots ii\end{cases}

cancel out y from the second equation:

\displaystyle  \begin{cases}   \displaystyle 2x - y= 3 \dots \dots i\\ x = 2y \dots  \dots ii\end{cases}

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simplify:

\displaystyle  \begin{cases}   \displaystyle 3y= 3 \\ x = 2y \end{cases}

divide both sides by 3:

\displaystyle  \begin{cases}   \displaystyle y= 1 \\ x = 2y \end{cases}

substitute the value of y to the second equation which yields:

\displaystyle  \begin{cases}   \displaystyle y= 1 \\ x = 2 \end{cases}

<h3>Question-3:</h3>

by order pair we obtain;

\displaystyle  \begin{cases}   \displaystyle  2p  + q = 2 \dots \dots i\\3q  + 2p =  3 \dots  \dots ii\end{cases}

rearrange:

\displaystyle  \begin{cases}   \displaystyle  2p  + q = 2 \\2p  +  3q=  3 \end{cases}

subtract and simplify

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substitute the value of q to the first equation:

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make q the subject of the equation:

\displaystyle p =   \frac{3}{4}

hence,

\displaystyle  q =  \frac{1}{2} \\ p =   \frac{3}{4}

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